w/w-5-5w/5w-4=w-2/5w^2-29w+20

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Solution for w/w-5-5w/5w-4=w-2/5w^2-29w+20 equation: 


D( w )

w = 0

w = 0

w = 0

w in (-oo:0) U (0:+oo)

w/w-(((5*w)/5)*w)-5-4 = w-((2/5)*w^2)-(29*w)+20 // - w-((2/5)*w^2)-(29*w)+20

(2/5)*w^2-(((5*w)/5)*w)-w+29*w+w/w-20-5-4 = 0

(2/5)*w^2-w^2-w+29*w+w/w-20-5-4 = 0

28*w-3/5*w^2-28 = 0

DELTA = 28^2-(-28*(-3/5)*4)

DELTA = 3584/5

DELTA > 0

w = ((3584/5)^(1/2)-28)/(-3/5*2) or w = (-(3584/5)^(1/2)-28)/(-3/5*2)

w = -5/6*((3584/5)^(1/2)-28) or w = 5/6*((3584/5)^(1/2)+28)

w in { -5/6*((3584/5)^(1/2)-28), 5/6*((3584/5)^(1/2)+28) }

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